Question

What is the molality when 0.75 mol is dissolved in 2.50 L of solvent?

Answer 1

To answer this question we will assume that the solvent is water. The mass of the solvent will be 2.50kg.

NOTE: The density of water is 1g = 1mL

`(2.50 L)/(1)`x`(1000 mL)/(1 L)`x`(1 g)/(1 mL)`x`(1 kg)/(1000g)`= 2.50 kg

To calculate the molality we use the relationship-

`(mol solute)/(kg solvent)` = molality

`(0.75 mol solute)/(2.50 kg solvent)` = 0.30`m`