What are the characteristics of the simple harmonic motion on a spring?

1 Answer
Sep 15, 2014

The acceleration is proportional to the displacement (x) of the mass and it acts toward the equilibrium position.


The defining equation for any type of SHM is:
#x = – ω² a#
where #ω = 2πf#
The negative indicates that the acceleration always acts toward the equilibrium.

In the plane of the oscillation for a horizontal mass–spring system the only (significant) force is the tension in the spring.
From Hooke’s Law:
#T = kx#
Also the mass is not changing so we can apply the simplified form of Newton’s second law of motion to this example:
#T = ma#
Therefore, #ma = kx ⇒ a = (k/m)x#.

As you can see that satisfies the first condition of SHM as #k/m# is a constant, therefore #a prop x#. That equation only tells us about the magnitude of the acceleration. If we were to draw a diagram we would see in addition that the force and therefore the acceleration acts toward the equilibrium (the second condition of SHM).