Question

How do you find the general indefinite integral of `(13x^2+12x^-2)dx`?

Answer 1

The answer is: `13/3x^3-12x^-1+c`

Using this integral:

`int[f(x)]^nf'(x)dx=[f(x)]^(n+1)/(n+1)+c`.

So:

`int(13x^2+12x^-2)dx=13x^(2+1)/(2+1)+12x^(-2+1)/(-2+1)+c=`

`=13/3x^3-12x^-1+c`.