How do you factor by grouping $xy+4x-2y-8$ ?

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Answer 1 · 2015-04-15T12:02:43

Try collecting $y$ between the first and third term and $4$ between the second and the fourth:
$y(x-2)+4(x-2)=$ now collect $(x-2)$ ;
$(x-2)(y+4)$

How do you factor by grouping xy+4x-2y-8xy+4x-2y-8?