How do you factor by grouping: #xy - 2y + 2x - 4#?

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Answer 1 · 2015-04-18T21:43:51

Collect #y# between the first and second and #2# between the third and fourth:
#y(x-2)+2(x-2)=#
Collect #(x-2#;
#=(x-2)(y+2)#