How do you find the integral of #(7x^(3) -5) (2x^(2) +9) dx#?

1 Answer
Apr 23, 2015

You can multiply the two brackets to get:
#int(14x^5+63x^3-10x^2-45)dx=#
and integrate, separating each term of your integral as a single integral (integral of a sum/difference is equal to the sum/difference of integrals) and using the fact that: #intkx^ndx=kx^(n+1)/(n+1)+c# where #k# is a constant and that #intkdx=kx+c#