How do you factor by grouping $y^{3} + y + 2 y^{2} + 2$ $y^3+y+2y^2+2$ ?

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Answer 1 · 2015-05-09T22:31:59

$y^{3} + y + 2 y^{2} + 2$ $y^3+y+2y^2+2$

$(y^{3} + y) + (2 y^{2} + 2)$ $(y^3+y)+(2y^2+2)$

Factor $y$ $y$ out of the first term.

$y (y^{2} + 1)$ $y(y^2+1)$

Factor $2$ $2$ out of the second term.

$2 (y^{2} + 1)$ $2(y^2+1)$

The common factor is $(y^{2} + 1)$ $(y^2+1)$ .

$y (y^{2} + 1) + 2 (y^{2} + 1)$ $y(y^2+1)+2(y^2+1)$ =

$(y + 2) (y^{2} + 1)$ $(y+2)(y^2+1)$

How do you factor by grouping y3+y+2y2+2y^3+y+2y^2+2?