Question

How do you write the quadratic in vertex form given `y=x^2+4x-7`?

Answer 1

`y = x^2+4x-7 = (x+2)^2 - 11`

In general, for `y = ax^2 + bx + c`, the `x` coordinate of the vertex is `-b/(2a)`, and the vertex form is:

`y = a(x + b/(2a))^2 + (c - b^2/(4a))`