How do you write $y= 4x^2 + 16x + 23$ into vertex form?

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Answer 1 · 2015-05-13T03:12:08

$(-b/2a) = -16/8 = -2$

$f(-b/2a) = f(-2) = 16 - 32 + 23 = 7$

Factored form: $f(x) = 4(x + 2)^2 + 7$

Check:
Develop: $f(x) = 4(x^2 + 4x + 4) + 7 = 4x^2 + 16x + 23.$ Correct

How do you write y= 4x^2 + 16x + 23y= 4x^2 + 16x + 23 into vertex form?