How do you write #y = 2x^2 + 20x + 50# in standard form? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer George C. May 15, 2015 #y = 2x^2+20x+50# is already in what many people call standard form, but sometimes the term "standard form" is used to denote vertex form: #y = a(x-h)^2 + k# In our case #y = 2x^2+20x+50 = 2(x+5)^2 = 2(x-(-5))^2 + 0# in vertex form with #a=2#, #h=-5# and #k=0#. Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 4292 views around the world You can reuse this answer Creative Commons License