Question

How do you write `Y = 3x^2 - 6x - 2` in vertex form and identify the vertex, y intercept and x intercept?

Answer 1

x of vertex:
`(-b/2a) = 6 /6 = 1`

y of vertex: f(1) = 3 - 6 -2 = -5

Factored form:`f(x) = a(-b/2a)^2 + f(-b/2a)`=

`f(x) = 3(x - 1)^2 - 5`

Check by developing: `f(x) = 3(x^2 - 2x + 1) - 5 = 3x^2 - 6x -3.` OK