Question

How do you write `4x^2-4x+2` in vertex form?

Answer 1

Given `y=4x^2-4x+2`

The general vertex form is
`y = m(x-a)^2+b` where `(a,b)` is the vertex of the parabola

Extract `m`
`y=4(x^2-x) +2`

Complete the square
`y= 4(x^2-x+1/4) +2 +1`

Rewrite in vertex form
`y=4(x-1/2)+3`