How do you factor by grouping $9 x^{2} + 3 x y + 3 x + y$ $9x^2 + 3xy + 3x + y$ ?

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Answer 1 · 2015-05-23T19:37:10

$9 x^{2} + 3 x y + 3 x + y$ $9x^2+3xy+3x+y$

$= (9 x^{2} + 3 x y) + (3 x + y)$ $= (9x^2+3xy)+(3x+y)$

$= 3 x (3 x + y) + (3 x + y)$ $= 3x(3x+y)+(3x+y)$

$= (3 x + 1) (3 x + y)$ $= (3x+1)(3x+y)$

How do you factor by grouping 9x^2 + 3xy + 3x + y9x2+3xy+3x+y9x^2 + 3xy + 3x + y?