Question

How do you write the quadratic in vertex form given `y= x^2-6x+15`?

Answer 1

Vertex form is written by completing the square in the equation. Here y=`x^2 -6x+15`

=`x^2 -6x +9 -9 +15` { Half the coefficent of x and square it, then add and subtract that number]

= `(x-3)^2 +6`

The equation is therefore y-6= `(x-3)^2` which is in the required format. Vertex is (3,6)