Question

How do you use the law of sines to solve the triangle given A = 14.9°, B = 98.1°, b = 18.6?

Answer 1

Use the trig identity: `a/sin A = b/sin B`

`a = b(sin A)/(sin B) = 18.9(0.257/0.99)` = 18.9(0.26) = 4.90

C = 180 - A - B = 180 - 14.9 - 98.1 = 67 deg

`c = b(sin C/sin B) = 18.9(0.92/0.99) = 18.9(0.93) = 17.57`