How do you find the vertex of a parabola #y= -5[x+2]^2#?

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Answer 1 · 2015-07-18T21:44:09

The vertex is at #color(red)((-2,0)#.

The vertex form of the equation for a parabola is:

#y = a(x - h)^2 + k#, where (#h, k#) is the vertex of the parabola.

We can re-write your equation as

#y = -5(x+2)^2 + 0#

By comparing your equation with the vertex form, we see that

#h = -2# and #k = 0#.

The vertex is at (#-2,0#).

graph{y = -5(x+2)^2 [-5,2 , -5, 2]} #