How do you evaluate #arctan((1/sqrt3)#?

1 Answer
Jul 22, 2015

#arctan(1/sqrt(3)) = pi/6 or 30^o#

Explanation:

This ratio is one of the standard trigonometric triangles:
enter image source here

#arctan# must provide an angle in quadrants one or four; in quadrant four, the argument would have needed to be negative.

The ratio # ((1/2))/((sqrt(3)/2)) = 1/sqrt(3)#
#color(white)("XXXX")#is that of a #pi/6# angle (as indicated above).