How do you find the vertex of $y = {(x - 3)}^{2}$ $y = (x - 3)^2$ ?

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Answer 1 · 2015-07-29T20:19:35

The vertex is at $(3, 0)$ $color(red)((3,0)$ .

$y = {(x - 3)}^{2}$ $y = (x -3)^2$

The vertex form for the equation of a parabola is

$y = a {(x - h)}^{2} + k$ $y = a(x-h)^2 + k$ , where ( $h, k$ $h, k$ ) is the vertex of the parabola.

We can re-write your equation as

$y = {(x - 3)}^{2} + 0$ $y = (x -3)^2 + 0$

By comparing the two equations, we see that $h = 3$ $h = 3$ and $k = 0$ $k = 0$ .

The vertex is at ( $3, 0$ $3,0$ ).

Graph Graph

How do you find the vertex of y = (x - 3)^2y=(x−3)2y = (x - 3)^2?