How do you express the complex number in trigonometric form # 2(cos 90° + i sin 90°)#?

1 Answer
Jul 30, 2015

In a sense, it's already in trigonometric form. Other common ways to write it, which may be what you are after, are #2\mbox{cis}(90^{circ})# and #2e^{i*90^{circ})=2e^{i*pi/2}#.

Explanation:

The second form follows from Euler's formula: #e^{i theta}=cos(theta)+i sin(theta)#.

The "cis" form of the answer is just another way to write it (#mbox{cis}(theta)# is a symbol that is, by definition, equal to #cos(theta)+i sin(theta)#).

All of this can also be thought of in terms of polar coordinates in the complex plane. The polar coordinates of the complex number #2(cos(90^{circ})+i sin(90^{circ}))=2i# are #(r,theta)=(2,90^{circ})# (its rectangular coordinates are #(x,y)=(0,2)#).