How do you find the vertex of #y= x^2-8x+5#?
2 Answers
The simplest method for finding the vertex of the given polynomial is to convert it into "vertex form" to find the vertex at
Explanation:
Given
If we can convert this into vertex form:
then the vertex will be at
The easiest way to do this conversion is via a "completion of the square method"
If
then the third term needs to be
So we add (and then subtract
Simplifying:
So the vertex is at
Find vertex of f(x) = x^2 - 8x + 5
Ans: Vertex (4, -11)
Explanation:
x-coordinate of vertex:
y-coordinate of vertex: