How do you find the vertex of #f(x)=-5/2x^2+10x+1/3#?
1 Answer
Aug 7, 2015
The vertex is at
Explanation:
The general vertex form for a quadratic is
Given
Extract the
Complete the square
Write as a squared binomial and simplfy
Note that this is in explicit vertex form.
The graph looks like: graph{-5/2x^2+10x+1/3 [-12.22, 16.25, -2.78, 11.46]}