Question

How do you find the vertex and axis of symmetry for `y = -3x^2 + 18x - 13`?

Answer 1

Vertex of `y = -3x^2 + 18x - 13`

Ans: Vertex (3, 14)

Explanation:

x-coordinate of vertex: `x = (-b/2a) = -18/-6 = 3`
y-coordinate of vertex: y = f(3) = -27 + 54 - 13 = 14
x-coordinate of the axis of symmetry is the same as the x-coordinate of the vertex: x = 3