A chemist mixes a 200 L of a solution that is 60% acid with a 300 L of a solution that is 20% acid. What is the percentage of the mixture?

1 Answer
Aug 11, 2015

The resulting mixture is 36% acid.

Explanation:

The resulting mixture's acid proportion is

"volume of acid in the solution"/"volume of the solution"

The volume of the mixture is 200+300=500L

The volume of acid in the first solution is 0.6*200=120L

The volume of acid in the second solution is 0.2*300=60L

Therefore, the resulting mixture's acid proportion is:

(120+60)/500=180/500=36%