What is the antiderivative of #2x#?

1 Answer
Sep 1, 2015

There are many antiderivatives of #2x#. The (most) general antiderivative is #x^2 +C#

Explanation:

An antiderivative of #2x# is a function whose derivative is #2x#:

antiderivatives include:

#x^2#, #" "x^2+7#, #" "x^2+19#, #" "x^2-11#, #" "x^2+(17pi)/8 - sqrt 21#

#x^2 +sin^2x+cos^2x#

Any (every) function that can be expressed in the form #x^2 + "some constant"# is an antiderivative.

The general antiderivative is expressed by choosing one of the antiderivatives and adding an "arbitrary constant" usually named #C#

It is convenient (but not required) to choose the first antiderivative on the list above and say:

The (most) general antiderivative of #2x# is #x^2 + C#.

Strange but true
According to the definition of general antiderivative, we can also say "The (most) general antiderivative of #2x# is #x^2+sin^2x+cos^2x+19sqrtpi - sqrt37/4 +C#"

Important! -- check you textbook's definition (and your grader's sense of humor) before using this smart-alecky answer on an exam!