How do you evaluate #arcsin 1#?

1 Answer
Alan P.
Sep 7, 2015

#arcsin(1) = pi/2#

Explanation:

#arcsin# is defined as having a range restricted to #[-pi/2,+pi/2]#

If #arcsin(1) = theta color(white)("XX")rarrcolor(white)("XX")sin(theta)=1#

That is for #theta in [-pi/2,+pi/2]# with a unit circle, the ratio of the opposite side (y-coordinate) to the hypotenuse must be #=1#

The only angle meeting this requirement is #theta= pi/2#

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