How do you find the amplitude and period of #y = -2 sin (1/2) x#?

1 Answer
Oct 2, 2015

Amplitude is #2# and period is #4pi#

Explanation:

For a general sine graph of form #y=asinbx#, the amplitude is #|a|# and the period is #(2pi)/b#

So in this case the amplitude is #2# and the period is #(2pi)/(1//2)=4pi#

This means that the maximum displacement from the rest position or x axis is 2 units, and the time taken for 1 complete cycle on the x-axis is #4pi# radians.