How do you find the slope and y intercept of $4 x - 3 y = - 9$ $4x-3y = -9$ ?

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Answer 1 · 2015-10-16T13:55:48

Slope is $\frac{4}{3}$ $4/3$ and y-intercept is $3$ $3$

First write in standard linear form $y = m x + c$ $y=mx+c$ then m is the gradient or slope and c is the y-intercept.

Hence in this case, : $4 x - 3 y = - 9 \Rightarrow y = \frac{4 x + 9}{3} = \frac{4}{3} x + 3$ $4x-3y=-9 => y=(4x+9)/3=4/3x+3$

graph{4/3x+3 [-14.24, 14.23, -7.12, 7.12]}

How do you find the slope and y intercept of 4x-3y = -94x−3y=−94x-3y = -9?