How do you find the axis of symmetry and vertex point of the function: # y = -x^2 + 3x + 5#?

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Answer 1 · 2015-10-18T05:12:10

Vertex #(3/2, 29/4)#

Axis of Symmetry #x=3/2#

Given -

#y=-x^2+3x+5#

Vertex point -

#x=(-b)/(2a)=(-3)/(2 xx(-1))=(-3)/(-2)=3/2#

#y=-(3/2)^2+3(3/2)+5#

#y=(-9+18+20)/4=29/4#

Vertex #(3/2, 29/4)#

Axis of Symmetry #x=3/2#