How do you find the axis of symmetry and vertex point of the function: #f(x)= 3x^2+12x-6#?

1 Answer
Oct 19, 2015

The vertex is #(1,9)#
The axis of symmetry is #x=1#

Explanation:

To find the axis of symmetry of the function, use the coefficients of the equation and the formula #x = -b/2a#

For the function #f(x) = 3x^2 + 12x - 6#
#a = 3#
#b = 12#
#c = -6#

The x of the vertex and the axis of symmetry can be found by
#-b/2a#
#-12/(2(-6))#
#x = 1#

This means the x of the vertex is x = 1 which is also the line of symmetry for the function.

To find the y of the vertex, plug x = 1 into the function and solve for y

#y = 3(1)^2 + 12(1) -6#
#y = 3 + 12 -6#
#y = 9#

Therefore the vertex point is #(1 , 9)#