Question

How do you find the derivative of `sin^2 (2x+3)`?

Answer 1

`d/dx[sin^2(2x+3)]=4sin(2x+3)cos(2x+3)`

Explanation:

Use the power rule, and other differentiation rules, to get

`d/dx[sin^2(2x+3)]=2sin(2x+3)*cos(2x+3)*2`