What are the area and the perimeter of an isosceles triangle with base of 11.3 cm and height of 26 cm?

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Answer 1 · 2015-11-16T05:49:06

Using the figure below we have that

enter image source here

The area of the triangle is

#E=1/2b*(h_b)=1/2*11.3*26=146.9 cm^2#

In order to find the perimeter, we need to find the side #a# (figure)
hence from Pythagorean Theorem we have that

#a^2=(h_b)^2+(b/2)^2=>a=sqrt(26^2+5.65^2)=>a=26.6#

So the perimeter is

#T=a+a+b=2a+b=2*26.6+11.3=64.5cm#