How do you simplify #5i^4 + 3i^2 + 4i^7 - 4#? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer Trevor Ryan. Nov 17, 2015 #-2-4i# Explanation: We may use the fact that #i^2=-1# to write the following #5i^4+3i^2+4i^7-4=5(i^2*i^2)+3i^2+4(i^2*i^2*i^2*i)-4# #=5-3-4i-4# #=-2-4i# Answer link Related questions How do I use DeMoivre's theorem to find #(1+i)^5#? How do I use DeMoivre's theorem to find #(1-i)^10#? How do I use DeMoivre's theorem to find #(2+2i)^6#? What is #i^2#? What is #i^3#? What is #i^4#? How do I find the value of a given power of #i#? How do I find the #n#th power of a complex number? How do I find the negative power of a complex number? Write the complex number #i^17# in standard form? See all questions in Powers of Complex Numbers Impact of this question 1433 views around the world You can reuse this answer Creative Commons License