Question

How do you calculate the `sin(sin^-1 (1/3))`?

Answer 1

`sin(sin^-1(1/3))` `=` `1/3`

Explanation:

You can just use B.E.D.M.A.S to evaluate this equation, by doing `sin^-1(1/3)`, you get `~~19.47`.
Then take the `sin` of `19.47` which ultimately gives you the same thing back. `1/3`

Answer 2

`1/3`

Explanation:

`1/x*x=1`

`x-x=0`

`sqrt(x^2)=x`

`10^(logx)=x`

All of these are examples of functions and identities that undo one another. Another example of similar functions are `sin` and `sin^-1`.

`sin(sin^-1(x))=x`

`sin(sin^-1(1/3))=1/3`