Question

The density of gasoline at 29°C is .6 g/mL. What is the mass of 6 liters of gasoline?

Answer 1

Under `4*kg`.

Explanation:

Density, `rho` `=` `("mass")/("volume")`; thus `"mass" = rhoxx"volume"`

`6cancelL xx 1000*cancel(mL)*cancel(L^-1) xx 0.6*g*cancel(mL^-1)`

`=` `??g`

The volume was quoted at a certain temperature because volume varies with temperature. If the temperature had been `15` `""^@C`, would you expect volume to increase or decrease? Why?

Answer 2

The mass will be 3600 g of gasoline.

Explanation:

Since density is in g/mL, convert 6 L to mL.

`6cancel"L"xx(1000"mL")/(1cancel"L")=6000"mL"`

To calculate the mass of 6000 mL of gasoline, multiply the volume times its mdensity.

`6000cancel"mL"xx(0.6"g")/(1cancel"mL")="3600 g gasoline"`