While you cook on your gas grill, 3.7 grams of CO_2 are produced. How many moles of propane, C_3H_8 are used, using the equation C_3H_8+5O_2 -> 3CO_2+4H_2O?

1 Answer
MAT
Dec 2, 2015

0.084 moles of C_3H_8

Explanation:

Given mass of CO_2 = 3.7g
Molar mass of CO_2 = 12+2(16)= 44g/mol
No of moles of CO_2 produced = ("given mass")/("molar mass") = 3.7/44 =0.084mol

According to balanced equation;
3 moles of CO_2 requires = 1 mole of C_3H_8
Thus, 0.084 moles of CO_2 will require= 1/3 xx 0.084mol of C_3H_8
= 0.028mol of C_3H_8
So, 0.028mol of C_3H_8 are used to produce 3.7g of CO_2

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