Question

Given the equation: Cu + AgNO3 --> Ag + CuNO3, what mass of silver in grams is precipitated when 40.0 g of copper reacts with an excess of silver nitrate in solution?

Answer 1

`68.0g` of silver.

Explanation:

The reaction is:

`Cu(s)+AgNO_3(aq)->Ag(s)+CuNO_3(aq)`

Since the silver nitrate is in excess, then copper is the limiting reactant , and therefore, its mass will be used to calculate the mass of silver that will form:

`?gAg=40.0cancel(gCu)xx(cancel(1molCu))/(63.5cancel(gCu))xx(1cancel(molAg))/(1cancel(molCu))xx(107.9Ag)/(1cancel(molAg))=68.0gAg`