What is the vertex of $y = {(x - 4)}^{2}$ $y=(x-4)^2$ ? Thank you so much, in advance.?

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Answer 1 · 2015-12-13T05:31:37

Vertex of $y = {(x - 4)}^{2}$ $y = (x - 4)^2$
Vertex (-4, 0)

This is the vertex form of y.
x-coordinate of vertex: x = 4
y-coordinate of vertex: y = 0

What is the vertex of y=(x−4)2y=(x-4)^2? Thank you so much, in advance.?