Can $y = 7 x^{3} - 4 x^{2} + 8 x$ $y=7x^3-4x^2+8x$ be factored? If so what are the factors ?

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Can $y = 7 x^{3} - 4 x^{2} + 8 x$ $y=7x^3-4x^2+8x$ be factored? If so what are the factors ?

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Answer 1 · 2015-12-17T03:26:28

Factor $y = 7 x^{3} - 4 x^{2} + 8 x$ $y = 7x^3 - 4x^2 + 8x$

Explanation:

$y = x Y = x (7 x^{2} - 4 x + 8)$ $y = xY = x(7x^2 - 4x + 8)$ . Factor Y.
D = b^2 - 4ac = 16 - 224 < 0. Since D < 0, there are no real roots, therefor, Y can't be factored.
Finally: $y = x (7 x^{2} - 4 x + 8)$ $y = x(7x^2 - 4x + 8)$

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Can $y = 7 x^{3} - 4 x^{2} + 8 x$ $y=7x^3-4x^2+8x$ be factored? If so what are the factors ?

1 Answer

Explanation:

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Can y=7x3−4x2+8xy=7x^3-4x^2+8x be factored? If so what are the factors ?

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Explanation:

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Can $y = 7 x^{3} - 4 x^{2} + 8 x$ $y=7x^3-4x^2+8x$ be factored? If so what are the factors ?