How do you factor $y = 3 x^{3} - 300 x$ $y=3x^3-300x$ ?

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How do you factor $y = 3 x^{3} - 300 x$ $y=3x^3-300x$ ?

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Answer 1 · 2015-12-18T14:22:12

$y = 3 x (x^{2} - 100)$ $y = 3x(x^2 - 100)$

Explanation:

There is at least one $x$ $x$ on every term at the right so you can already factorize by $x$ $x$ , which gives you $y = x (3 x^{2} + 300)$ $y = x(3x^2 + 300)$ .

But 300 and 3 both have 3 as common divisor, so you can also say that $y = 3 x (x^{2} - 100)$ $y = 3x(x^2 - 100)$ . I hope that answers your question.

Answer 2 · 2015-12-18T16:18:39

$y = 3 x (x - 10) (x + 10)$ $y=3x(x-10)(x+10)$

Explanation:

Factoring out $3 x$ $3x$ gives:

$y = 3 x (x^{2} - 100)$ $y=3x(x^2-100)$

But $100$ $100$ is $10^{2}$ $10^2$ giving:

$y = 3 x (x^{2} - 10^{2})$ $y=3x(x^2-10^2)$

Known: $(a^{2} - b^{2}) = (a - b) (a + b)$ $(a^2-b^2)=(a-b)(a+b)$

Applying this to our question gives:

$y = 3 x (x - 10) (x + 10)$ $y=3x(x-10)(x+10)$

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How do you factor $y = 3 x^{3} - 300 x$ $y=3x^3-300x$ ?

2 Answers

Explanation:

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Science

Math

Humanities

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How do you factor y=3x3−300xy=3x^3-300x ?

2 Answers

Explanation:

Explanation:

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Impact of this question

How do you factor $y = 3 x^{3} - 300 x$ $y=3x^3-300x$ ?