A triangle has sides A, B, and C. The angle between sides A and B is #pi/12# and the angle between sides B and C is #pi/12#. If side B has a length of 3, what is the area of the triangle?

1 Answer
Dec 23, 2015

Area #= 9/(4(2+sqrt(3)))#

Explanation:

(see diagram)
enter image source here

By Half Angle Formula for #tan#
#color(white)("XXX")tan(pi/12) = sin(pi/6)/(1+cos(pi/6))#
using standard values for #sin# and #cos#
#color(white)("XXX")tan(pi/12)= 1/(2+sqrt(3))#

The height of the triangle is
#color(white)("XXX")h=3/2 xx tan(pi/12)#

and the area is
#color(white)("XXX")("base " xx " height")/2#

#color(white)("XXX")=(3xx3/2xxtan(pi/2))/2#

#color(white)("XXX")=9/4xx1/(2+sqrt(3))#