How do you solve the system by graphing #2x+y=10# and #3x+4y=0#?

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Answer 1 · 2015-12-27T14:35:29

The solution for the system of equations is

#color(blue)(x=8,y=-6#

#2x+y=10#, multiplying by #4#
#8x+color(blue)(4y)=40#....equation #(1)#

#3x+color(blue)(4y)=0#.......equation #(2)#

Solving by elimination:

Subtracting equation #2# from #1#:

#8x+cancelcolor(blue)(4y)=40#

#-3x-cancelcolor(blue)(4y)=-0#

#5x=40#

#color(blue)(x=8#

Finding #y# by substituting #x# in equation #1#

#2x+y=10#

#y=10 -2x#

#y=10 -2 xx color(blue)(8#

#y=10 -16#

#color(blue)(y=-6#