A triangle has sides A, B, and C. The angle between sides A and B is #(pi)/2# and the angle between sides B and C is #pi/12#. If side B has a length of 12, what is the area of the triangle?

1 Answer
Dec 30, 2015

#Area = S = 19.292#

Explanation:

If the angle between A and B is #pi/2# then the triangle is a right one and its area is:
#S = (A*B)/2#

Since the angle between B and C is known and the length of B also is known, we can find A in this way:
#tan (pi/12) = ("opposed cathetus")/("adjacent cathetus")#
So #tan (pi/12) = A/B# => #A = B*tan(pi/12)#

Finally,
#S = (B^2*tan(pi/12))/2#
#S = (12^2*0.267949)/2 = 19.292#