Question

What is the vertex form of `y= 6x^2 + 12x – 48`?

Answer 1

`y = 6(x+1)^2 -54`

Explanation:

First simplify the expression
`y = 6(x^2 +2x - 8)`
Then use completing the square
`y = 6((x+1)^2 - 9)`
`y = 6(x+1)^2 -54`
The vertex is `(-1,-54)`