What is the vertex of # y=x^2-4x+3 #?

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Answer 1 · 2016-01-04T00:45:53

The x-coordinate can be found using a simple formula ...

The general form of a quadratic is #y=ax^2+bx+c#

For this problem, #a=1, b=-4, c=3#

#x=(-b)/(2a)=-(-4)/(2xx1)=2#

Now that we now the x-coordinate of the vertex is #2#, insert it into the equation to find y ...

#y(2)=2^2-4(2)+3=-1#

Vertex #=(2,-1)#

hope that helped

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