Question

A circuit with a resistance of `8 Omega` has a fuse with a capacity of `3 A`. Can a voltage of `36 V` be applied to the circuit without blowing the fuse?

Answer 1

No. The fuse will blow.

Explanation:

According to Ohm's Law, the total current flowing in a closed circuit is directly proportional to the total potential difference applied across the circuit.

`V=IR`.

So in this case, `I_T=(V_T)/(R_T)=(36V)/(8Omega)=4,5A`.

Therefore the `3A` fuse will blow since `4,5A>3A`.