Question

Question #cbe8e

Answer 1

`M_1=2.5M`

Explanation:

Since the number of mole remains the same, we can then say:

`M_1V_1=M_2V_2`

Where, `M_1=?`, `V_1=10mL`, `M_2=0.1M` and `V_2=250mL`.

The concentration of the stock solution is then found by:

`=>M_1=(M_2V_2)/(V_1)=(0.1Mxx250cancel(mL))/(10 cancel(mL))=2.5M`