Question

What is the antiderivative of `1/(x^2)`?

Answer 1

`-1/x+C`

Explanation:

Use the antiderivative rule

`intx^ndx=(x^(n+1))/(n+1)+C`

This can be applied to the current function since `1/x^2=x^-2`.

`intx^-2dx=(x^(-2+1))/(-2+1)+C=(x^-1)/(-1)+C=-1/x+C`