Question

What is the equation of the circle with a center at `(2 ,2 )` and a radius of `3`?

Answer 1

`(x-2)^2+(y-2)^2=9`

Explanation:

The standard form of a circle with a center at `(h,k)` and a radius `r` is

`(x-h)^2+(y-k)^2=r^2`

Since the center is `(2,2)` and the radius is `3`, we know that

`{(h=2),(k=2),(r=3):}`

Thus, the equation of the circle is

`(x-2)^2+(y-2)^2=3^2`

This simplifies to be

`(x-2)^2+(y-2)^2=9`