How do you find the vertex of the quadratic equation #y = –4(x + 6)^2 + 2#?

1 Answer
Jan 28, 2016

The vertex is #(-6,2)#.

Explanation:

#y=-4(x+6)^2+2# is the vertex form for a parabola, #y=a(x-h)^2+k#, where #a=-4, h=-6, k=2#.

The vertex of a parabola is the minimum or maximum point of a parabola. Since #a<0#, the parabola opens downward and the vertex is the maximum point. The vertex of a parabola represented by the vertex form is #(h,k)#.

Therefore, the vertex for this parabola is #(-6,2)#.

graph{y=-4(x+6)^2+2 [-10, 10, -2.12, 7.88]}