Question

How do you find the vertex of the quadratic equation `y = –4(x + 6)^2 + 2`?

Answer 1

The vertex is `(-6,2)`.

Explanation:

`y=-4(x+6)^2+2` is the vertex form for a parabola, `y=a(x-h)^2+k`, where `a=-4, h=-6, k=2`.

The vertex of a parabola is the minimum or maximum point of a parabola. Since `a<0`, the parabola opens downward and the vertex is the maximum point. The vertex of a parabola represented by the vertex form is `(h,k)`.

Therefore, the vertex for this parabola is `(-6,2)`.

graph{y=-4(x+6)^2+2 [-10, 10, -2.12, 7.88]}