What is the vertex of y= x^2- 6x + 14 ?

1 Answer
Jan 31, 2016

(3, 5)

Explanation:

The x-coordinate of the vertex of a parabola is given by -b/(2a). Remember that parabolas in standard form are ax^2+bx+c. With this in mind, we can see that, for our parabola, a = 1, b = -6, and c = 14.

To find the x-coordinate of the vertex, we just plug in the value of a and b into -b/(2a):

Vertex = -(-6)/(2(1)) = 6/2 = 3

Now that we have the x, we plug it into our parabola to find y:

(3)^2-6(3)+14 = 9-18+14 = 5

Our y-coordinate is 5, meaning our vertex is the point (3,5).